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So where does everything stand?
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Hiller4Hyz09 Offline
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Post: #1
So where does everything stand?
If we win and KSU loses, we'll both be 11-5 in the MAC, but they would still be # 1 right?

Do we care about Ohio vs. Miami tonight? If Ohio wins, they'll both finish 10-6.
03-04-2011 09:06 AM
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wmubasketballsupporter Offline
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RE: So where does everything stand?
Here are the standings go into the last game round of games.

Kent State 11-4
Miami (OH) 10-5
Western Michigan 10-5
Ball State 9-6
Akron 9-6
Ohio 9-6
Buffalo 8-7
Bowling Green 7-8
Central Michigan 7-8
Northern Illinois 5-10
Eastern Michigan 4-11
Toledo 1-14

As I see it there are only 5 teams (BSU, Akron, Miami, Ohio and WMU) left with a chance at a #2,#3 or #4 seed in the tourney. Kent State has locked up the #1 Seed no matter what happens. The winner of the West (either BSU or WMU) gets the #2 seed so that leaves 4 teams for the #3 and #4 seeds.

If the Broncos lose at CMU and end up 10-6 in the MAC, I believe we still have a chance at the #3 or #4 seed. We own tiebreakers over Ohio and Miami due to a head to head victory over those teams. IMO it would be best for us if Ohio beats Miami resulting in each of these teams ending up with a 10-6 MAC record. If we end up tied with Miami and Ohio we own the tiebreakers over both of those teams and would get the #3 seed!

The team that can screw this up would be Akron. If they beat Kent St tonight they end up with a 10-6 record as well and they own the head to head tiebreaker with us. It is possible that BSU, WMU, Akron, Ohio and Miami all end up at 10-6. I know BSU would get the 2nd seed but how would the remaining teams get seeded in this scenario??? Anyone who can shed some light on these different scenarios, please do!

What is the worst case scenario for WMU as far a seeding for the tourney?

Go Broncos!!!
03-04-2011 09:27 AM
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gobaseline Offline
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Post: #3
RE: So where does everything stand?
WMU wins and there is nothing to worry about.

Personally, I would like Miami to take the starch out of Ohio. That's a team that is rolling (to use a West Side of Michigan term).
03-04-2011 10:00 AM
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wmubasketballsupporter Offline
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RE: So where does everything stand?
Here is the Tiebreaker Procedure direct from the MAC website:

TIE-BREAKER PROCEDURE


A. Head-to-head competition


B. Winning percentage* vs. ranked conference teams (top to bottom, regardless of division, vs. common opponents regardless of the number of times played)


C. Coin flip


*Winning percentage is used instead of record because of situation where teams do not play each other the same number of times. Therefore, a team that is 1-0 (1.000) would win the tiebreaker over a team that is 1-1 (.500).

Scenario #1: So if we win at CMU or if BSU loses to NIU we are the #2 seed!

Scenario #2: We end up 10-6. Miami beats Ohio and Akron beats KSU. That means KSU #1, BSU #2, Miami #3 and WMU tied with Akron. We lose the tiebreaker b/c of our loss to Akron. Akron #4 seed and WMU #5.

Scenario #3: We end up 10-6. Ohio beats Miami and Akron loses to KSU. The seeds would be KSU #1, BSU #2 and WMU tied with Miami and Ohio at 10-6. WMU owns the head to head tiebreaker with both of these teams. WMU gets #3 seed and Miami and Ohio go to a coin flip for the #4 and #5 seeds as the each would have won and lost a game against each other head to head and both lost to WMU.

Scenario #4: We end up 10-6. This is the CRAZIEST possible scenario. Ohio beats Miami and Akron beats KSU. The seeds would be KSU #1, BSU #2 and 4 teams tied at 10-6 (WMU, Akron, Miami and Ohio). In this scenario, I am not sure exactly who to interprete the Tiebreaker Procedure. This is my attempt however. You can't use head to head so go to tiebreaker #2. If I understand it rightit would be these teams records against KSU. Therefore, WMU (0-1=0%), Ohio (1-1=50%), Miami (1-1=50%), Akron (1-1=50%). So if I am right, WMU would get the #6 seed and Ohio, Miami and Akron fight for seeds #3 to #5.

Scenario #5: We end up 10-6. Miami and KSU both win tonight. Seeds are KSU #1, BSU #2, Miami #3 and WMU #4.

So IMHO, the best scenario is we win at CMU or BSU loses to NIU and we get the #2 seed.

The best scenario if we lose at CMU is if Ohio beat Miami and KSU beat Akron. We get the #3 seed.

The next best scenario is Miami beats Ohio and KSU beats Akron and we get the #4 seed.

After that we are on the outside looking in, if I interpreted the tiebreaker correctly.

My brain is hurting at this point. Please feel free to help me out. Thanks everyone and Go Broncos.
03-04-2011 10:17 AM
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FanofWMU Offline
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RE: So where does everything stand?
The way I see it is if Miami and Kent State both win, even if we lose at CMU we are assured a bye to Cleveland. Because this would mean that only four teams in the MAC have atleast 10 wins.

With this scenario (if we lose) I believe we would have the 4th seed. Kent State first, Ball State 2nd, Miami 3rd and then us 4th.

However, I would like to put all these scenarios aside and just win at CMU and then we know for sure we'd lock in the 2 seed in Cleveland and start out with a far better matchup.
03-04-2011 10:20 AM
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Hiller4Hyz09 Offline
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Post: #6
RE: So where does everything stand?
(03-04-2011 10:00 AM)gobaseline Wrote:  WMU wins and there is nothing to worry about.

Personally, I would like Miami to take the starch out of Ohio. That's a team that is rolling (to use a West Side of Michigan term).

East side and West side
Live together in perfect harmony
Side by side on computer keyboard
oh Lord
Why can't we?

From the regular season games, it seems like we match up pretty well with Miami and Ohio at this point. We can hang with Mr. Cooper!
03-04-2011 10:29 AM
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brovol Offline
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RE: So where does everything stand?
I don't care about the seedings right now. I want to be Co-Champions of the MAC regular season. That means Akron needs to win tonight, so that we can match KSU's MAC record with a win at CMU. Truthfully, an extra game in the MAC Tournament, against a lesser opponent, wouldn't necessarily be a bad thing for our post season prospects.
03-04-2011 11:29 AM
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Hiller4Hyz09 Offline
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RE: So where does everything stand?
(03-04-2011 11:29 AM)brovol Wrote:  I don't care about the seedings right now. I want to be Co-Champions of the MAC regular season. That means Akron needs to win tonight, so that we can match KSU's MAC record with a win at CMU. Truthfully, an extra game in the MAC Tournament, against a lesser opponent, wouldn't necessarily be a bad thing for our post season prospects.

I like that. And maybe the NIT will accidently pick us instead of KSU.
03-04-2011 01:27 PM
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axeme Offline
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Post: #9
RE: So where does everything stand?
Actually, Miami can still be the #1 seed if they, Akron, and CMU win. They would win a 2-way tiebreaker vs. KSU by having a better East division record.
03-04-2011 01:30 PM
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JSF Offline
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Post: #10
RE: So where does everything stand?
People keep bringing up the wrong tiebreak procedures. The MAC has done a terrible job of promoting these changes.
03-04-2011 01:54 PM
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axeme Offline
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Post: #11
RE: So where does everything stand?
(03-04-2011 10:17 AM)wmubasketballsupporter Wrote:  Here is the Tiebreaker Procedure direct from the MAC website:

TIE-BREAKER PROCEDURE


A. Head-to-head competition


B. Winning percentage* vs. ranked conference teams (top to bottom, regardless of division, vs. common opponents regardless of the number of times played)


C. Coin flip


*Winning percentage is used instead of record because of situation where teams do not play each other the same number of times. Therefore, a team that is 1-0 (1.000) would win the tiebreaker over a team that is 1-1 (.500).

OZoner is correct. These are not the current tiebreaker procedures. They were changed after last season.

The new ones are these:
Quote:MEN'S AND WOMEN'S BASKETBALL
TIE-BREAKER AND TOURNAMENT SEEDING PROCEDURES
[revised and adopted 5.25.2010]

TIE-BREAKER PROCEDURE
A. Head-to-head competition
B. Division Record (10 games)
C. Winning percentage* vs. ranked conference teams
(top to bottom, regardless of division, vs. common opponents regardless of the number of times played)
D. Coin flip

*Winning percentage is used instead of record because of situations where teams do not play each other the same number of times. Therefore, a team that is 1-0 (1.000) would win the tiebreaker over a team that is 1-1 (.500).

For multiple team ties:
1. Total won-lost record of games played among the tied teams
2. Two-team tie-breaker procedure goes into effect (refer to A).

NOTE: Once a three-team tie has been reduced to two teams, the two-team tiebreaker will go into effect.

TOURNAMENT SEEDING - MEN
The East and West Divisional Champions will secure the No. 1 and No. 2 seeds. The team with the best conference winning percentage will earn the No. 1 seed, with the other divisional champion automatically earning the No. 2 seed, regardless of winning percentage. The remaining teams will be seeded 3 through 12 based upon overall conference winning percentage, regardless of division. The top four (4) seeds will earn first round byes in the tournament.

TOURNAMENT SEEDING - WOMEN
Seeding for the women's tournament will based on overall conference record. Teams will be seeded 1 through 12. The top four (4) seeds will earn first round byes in the tournament.
(This post was last modified: 03-04-2011 02:06 PM by axeme.)
03-04-2011 02:05 PM
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wmubasketballsupporter Offline
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Post: #12
RE: So where does everything stand?
Well this new tiebreaker will actually helps us if we get into a multiple team tie with at 10-6 with BSU,Akron, Miami and Ohio. We would lose the Tiebreaker to BSU for the #2 seed but thanks to this rule we would get a #3 seed. The reason we get the #3 is because we have a better combined record head to head against these teams.

Now the only scenario that doesn't get us a top 4 seed is for Akron, Miami and BSU to all win and we lose to CMU. That would leave the top 4 seeds as Miami, BSU, Kent and Akron. All other combinations and scenarios land us with one of the top 2-4 seeds!

I love you axeme and ozoner. You helped the cause!
(This post was last modified: 03-04-2011 02:46 PM by wmubasketballsupporter.)
03-04-2011 02:44 PM
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